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Dec 17, 2022 at 20:00 comment added Pietro Majer and who knows, maybe fibonacci would have appreciated ;)
Dec 17, 2022 at 15:36 comment added Tito Piezas III @PietroMajer Looking at OEIS, it is either Martin Gardner (1961), David Wells (1997), or Simon Finch (2003). Mathematicians and physicists can be quite the irreverent and whimsical bunch. Consider WIMPs (weakly interacting massive particles) and MACHOs (massive compact halo objects). There's a lot of other examples. P.S. By coincidence, I just recently made a MSE post on the tribonacci constant. :)
Dec 17, 2022 at 8:56 comment added Pietro Majer (I wonder who invented such term as "Tribonacci". It seems somehow a lack of respect for the name of a person, even if he lived 800 years ago. What if e.g. one day they will call you "Trito Piezas" instead of "Piezas III" :-) ?)
Apr 13, 2017 at 12:19 history edited CommunityBot
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Dec 9, 2016 at 17:57 comment added reuns Rewriting $-\frac{1}{16\,\zeta_3}\left(\frac{\eta(\tau) }{\eta(2\tau)}\right)^8\; =\; \frac{\alpha+1}{\alpha^2-4}$, you want to show that $-\frac{1}{16^3} \eta^{24} ((u^2+1)^2-4u^2)^3 = \eta(2\tau)^{24} u^3 (u^2+2)^3$ an equality in $S_{12}(\Gamma_0(2))$, a finite dimensional vector space generated by ... so it reduces to computing a basis of $S_{12}(\Gamma_0(2))$ and the first few coefficients of the LHS and the RHS. The same method should work for $\frac{\alpha+1}{\alpha^2-4}=\frac{\beta+1}{\zeta_3\,(\beta^2-4)}$.
Dec 8, 2016 at 16:05 history edited Tito Piezas III CC BY-SA 3.0
Simplified
Dec 8, 2016 at 15:55 history edited Tito Piezas III CC BY-SA 3.0
More relevant details
Dec 8, 2016 at 14:19 history edited Tito Piezas III CC BY-SA 3.0
Better and shorter form
Dec 8, 2016 at 12:55 history edited Tito Piezas III CC BY-SA 3.0
More details.
Dec 8, 2016 at 6:00 history edited Tito Piezas III CC BY-SA 3.0
Equivalent form
Dec 8, 2016 at 4:49 history edited Tito Piezas III CC BY-SA 3.0
Details
Dec 8, 2016 at 4:36 history asked Tito Piezas III CC BY-SA 3.0