Timeline for An integral for the tribonacci constant and the general case
Current License: CC BY-SA 3.0
12 events
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Dec 17, 2022 at 20:00 | comment | added | Pietro Majer | and who knows, maybe fibonacci would have appreciated ;) | |
Dec 17, 2022 at 15:36 | comment | added | Tito Piezas III | @PietroMajer Looking at OEIS, it is either Martin Gardner (1961), David Wells (1997), or Simon Finch (2003). Mathematicians and physicists can be quite the irreverent and whimsical bunch. Consider WIMPs (weakly interacting massive particles) and MACHOs (massive compact halo objects). There's a lot of other examples. P.S. By coincidence, I just recently made a MSE post on the tribonacci constant. :) | |
Dec 17, 2022 at 8:56 | comment | added | Pietro Majer | (I wonder who invented such term as "Tribonacci". It seems somehow a lack of respect for the name of a person, even if he lived 800 years ago. What if e.g. one day they will call you "Trito Piezas" instead of "Piezas III" :-) ?) | |
Apr 13, 2017 at 12:19 | history | edited | CommunityBot |
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Dec 9, 2016 at 17:57 | comment | added | reuns | Rewriting $-\frac{1}{16\,\zeta_3}\left(\frac{\eta(\tau) }{\eta(2\tau)}\right)^8\; =\; \frac{\alpha+1}{\alpha^2-4}$, you want to show that $-\frac{1}{16^3} \eta^{24} ((u^2+1)^2-4u^2)^3 = \eta(2\tau)^{24} u^3 (u^2+2)^3$ an equality in $S_{12}(\Gamma_0(2))$, a finite dimensional vector space generated by ... so it reduces to computing a basis of $S_{12}(\Gamma_0(2))$ and the first few coefficients of the LHS and the RHS. The same method should work for $\frac{\alpha+1}{\alpha^2-4}=\frac{\beta+1}{\zeta_3\,(\beta^2-4)}$. | |
Dec 8, 2016 at 16:05 | history | edited | Tito Piezas III | CC BY-SA 3.0 |
Simplified
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Dec 8, 2016 at 15:55 | history | edited | Tito Piezas III | CC BY-SA 3.0 |
More relevant details
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Dec 8, 2016 at 14:19 | history | edited | Tito Piezas III | CC BY-SA 3.0 |
Better and shorter form
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Dec 8, 2016 at 12:55 | history | edited | Tito Piezas III | CC BY-SA 3.0 |
More details.
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Dec 8, 2016 at 6:00 | history | edited | Tito Piezas III | CC BY-SA 3.0 |
Equivalent form
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Dec 8, 2016 at 4:49 | history | edited | Tito Piezas III | CC BY-SA 3.0 |
Details
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Dec 8, 2016 at 4:36 | history | asked | Tito Piezas III | CC BY-SA 3.0 |