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Post Reopened by Suvrit, András Bátkai, Alexandre Eremenko, Yemon Choi, Willie Wong
Post Closed as "Not suitable for this site" by Michael Albanese, Misha, Wolfgang, Peter LeFanu Lumsdaine, R.P.
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Guntram
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fixed point and Does a certain contractive mapping have a fixed point?

Let $f:X\rightarrow X$ be a contractive mapping of a ompletecomplete metric space satisfying : $$d(f(x),f(y))\leq\alpha(d(x,y))d(x,y)$$ where $\alpha:R^+\rightarrow [0,1)$$\alpha:\mathbf{R}^+\rightarrow [0,1)$, and $\alpha(t_n)\rightarrow 1$ implies $t_n\rightarrow 0$

Does $f$ hashave a fixed point ??

Thank you  .

fixed point and contractive mapping

Let $f:X\rightarrow X$ be a contractive mapping of a omplete metric space satisfying : $$d(f(x),f(y))\leq\alpha(d(x,y))d(x,y)$$ where $\alpha:R^+\rightarrow [0,1)$, and $\alpha(t_n)\rightarrow 1$ implies $t_n\rightarrow 0$

$f$ has a fixed point ??

Thank you  .

Does a certain contractive mapping have a fixed point?

Let $f:X\rightarrow X$ be a contractive mapping of a complete metric space satisfying $$d(f(x),f(y))\leq\alpha(d(x,y))d(x,y)$$ where $\alpha:\mathbf{R}^+\rightarrow [0,1)$, and $\alpha(t_n)\rightarrow 1$ implies $t_n\rightarrow 0$

Does $f$ have a fixed point?

Thank you.

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Isra El
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fixed point and contractive mapping

Let $f:X\rightarrow X$ be a contractive mapping of a omplete metric space satisfying : $$d(f(x),f(y))\leq\alpha(d(x,y))d(x,y)$$ where $\alpha:R^+\rightarrow [0,1)$, and $\alpha(t_n)\rightarrow 1$ implies $t_n\rightarrow 0$

$f$ has a fixed point ??

Thank you .