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Dec 7, 2016 at 16:13 comment added Martin Hey, first of all, thanks for the reply. Please see my response in the edit-section above :).
Dec 7, 2016 at 16:11 history edited Martin CC BY-SA 3.0
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Dec 7, 2016 at 14:38 comment added Willie Wong If you are willing to make the equations inhomogeneous, then the boundary values $f(x,y,t)$ plays little role. If you let $\tau$ be a fixed smooth function such that $\tau |_{z = 0} = f$, then $$ \partial_{tt} (\sigma - \tau) = A(\sigma - \tau) - (\partial_{tt} \tau - A\tau)$$ so $\sigma - \tau$ solves an inhomogeneous problem with vanishing boundary condition at $z = 0$. For the linear wave equation this type of Dirichlet condition is enforced by antisymmetrizing: enforcing that $\tilde{\sigma}(\cdot,-z) = -\tilde{\sigma}(\cdot,z)$. Have you tried something like that?
Dec 6, 2016 at 22:07 history edited Martin CC BY-SA 3.0
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Dec 6, 2016 at 16:01 history asked Martin CC BY-SA 3.0