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Dec 5, 2016 at 14:25 comment added Noam D. Elkies I suppose you can also use a (formal) differential equation to prove this.
Dec 5, 2016 at 12:38 vote accept Matt Majic
Dec 5, 2016 at 5:54 comment added Fedor Petrov @Noam but why formal series $(1+t)^x=\sum \binom{x}{n} t^n$ satisfy this equality? It may be justified by some abstract nonsense like 'this is known for reals or for positive integers, but the coefficients are polynomials in $x,y$, thus it holds formally too.' This argument may be reduced to bit less abstract: 'both parts of CV are polynomials in $x,y$ of degree at most $\ell$, thus it suffices to check that their values agree for integers $x,y\geqslant 0, x+y\leqslant \ell$ (this triangle is an interpolating set for polynomials of degree at most $\ell$) , where identity is just obvious.'
Dec 5, 2016 at 4:32 comment added Noam D. Elkies Right, with the same generatingfunctionological explanation: $(1+t)^x (1+t)^y = (1+t)^{x+y}$.
Dec 5, 2016 at 4:15 history answered Fedor Petrov CC BY-SA 3.0