Timeline for Binomial ID $\sum_{k=m}^p(-1)^{k+m}\binom{k}{m}\binom{n+p+1}{n+k+1}=\binom{n+p-m}{n}$
Current License: CC BY-SA 3.0
4 events
when toggle format | what | by | license | comment | |
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Dec 5, 2016 at 0:54 | comment | added | Alexey Ustinov | @Matt Majic Yes, see mathworld.wolfram.com/GausssHypergeometricTheorem.html | |
Dec 5, 2016 at 0:27 | comment | added | Matt Majic | So this must equal $\binom{n+p-m}{n}$? | |
Dec 5, 2016 at 0:18 | review | Low quality posts | |||
Dec 5, 2016 at 0:53 | |||||
Dec 4, 2016 at 23:59 | history | answered | Igor Rivin | CC BY-SA 3.0 |