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Dec 1, 2016 at 0:21 comment added Marty I took the liberty of editing the opening for clarity and conciseness (since I know the person who posed the question).
Dec 1, 2016 at 0:20 history edited Marty CC BY-SA 3.0
Edited opening for clarity.
Dec 1, 2016 at 0:04 history edited Exit path CC BY-SA 3.0
deleted 9 characters in body
Nov 30, 2016 at 23:46 comment added Exit path @YCor Clearly $ab=0$ when $i+j >N$ or $a=b=0$ since $A_N$ is the last nonzero group in the direct sum. The other direction is the condition I'm more interested in
Nov 30, 2016 at 23:25 comment added Exit path @EricWofsey I edited to drop the tensor, does this make more sense?
Nov 30, 2016 at 23:25 history edited Exit path CC BY-SA 3.0
deleted 7 characters in body
Nov 30, 2016 at 23:23 comment added Exit path @EricWofsey It should be $ab \neq 0$ when $a,b \neq 0$.
Nov 30, 2016 at 23:22 comment added YCor The first sentence is indeed unclear (whenever... iff ... sounds weird)
Nov 30, 2016 at 23:19 comment added Eric Wofsey To be clear, are you asking that $ab\neq 0$ when $a,b\neq 0$ or that $ab\neq 0$ when $a\otimes b\neq 0$? It might be the case that $a\otimes b=0$ in $A_i\otimes_{A_0}A_j$ even if $a$ and $b$ are both nonzero.
Nov 30, 2016 at 23:16 review First posts
Nov 30, 2016 at 23:26
Nov 30, 2016 at 23:14 history asked Exit path CC BY-SA 3.0