Timeline for Definition of $\textrm{GSpin}_{2n}$ and its root datum
Current License: CC BY-SA 3.0
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| Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
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| Nov 30, 2016 at 13:25 | answer | added | Jeffrey Adams | timeline score: 2 | |
| Nov 27, 2016 at 14:44 | comment | added | Jim Humphreys | P.S. To correct my typo, it should read Spin$_{2n+1}$ in the second line. | |
| Nov 27, 2016 at 7:20 | answer | added | Marty | timeline score: 11 | |
| Nov 26, 2016 at 23:17 | history | edited | D_S | CC BY-SA 3.0 |
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| Nov 26, 2016 at 20:58 | comment | added | Jim Humphreys | Is there a need to consider only even orthogonal groups here? The group SO$_{2n+1}$ and its simply connected covering group Spin${2n+1}$ (of Lie type $B_n$) are comparable in many respects to the groups of type $D_n$. . | |
| Nov 26, 2016 at 16:03 | comment | added | Mikhail Borovoi | My previous comment answers your second question. What about your first question, the group ${\rm GSpin}_{2n}$ is defined in the cited paper in terms of its connected dual Langlands group. In other words, you know its root datum, see my previous comment. | |
| Nov 26, 2016 at 15:55 | comment | added | Mikhail Borovoi | By the definition in the cited paper, the connected dual Langland group to ${\rm GSpin}_{2n}$ is ${\rm GSO}_{2n}$. You find a definition of ${\rm GSO}_{2n}$ , say, in this thesis and compute its root datum. Then the dual root datum is the root datum of ${\rm GSpin}_{2n}$. | |
| Nov 26, 2016 at 15:40 | history | edited | D_S | CC BY-SA 3.0 |
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| Nov 26, 2016 at 15:27 | history | asked | D_S | CC BY-SA 3.0 |