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Nov 28, 2016 at 15:15 comment added Rodrigo de Azevedo The problem is that you are weighting some monomials more than others. More importantly, are you sure the corresponding symmetric matrix is circulant?
Nov 28, 2016 at 15:10 comment added Kurisuto Asutora Yes, it is commutative - I wrote it this way to point out the construction of the sum in a more visible way.
S Nov 28, 2016 at 14:11 history suggested Rodrigo de Azevedo
added tag to question
Nov 28, 2016 at 13:48 review Suggested edits
S Nov 28, 2016 at 14:11
Nov 28, 2016 at 13:46 answer added Rodrigo de Azevedo timeline score: 2
Nov 27, 2016 at 20:18 comment added Rodrigo de Azevedo If multiplication is commutative, why does $h$ contain both $x_1 x_3$ and $x_3 x_1$? Or, both $x_2 x_4$ and $x_4 x_2$?
S Nov 23, 2016 at 15:19 history suggested Ivan Izmestiev
added linear algebra tag
Nov 23, 2016 at 15:17 vote accept Kurisuto Asutora
Nov 23, 2016 at 14:08 review Suggested edits
S Nov 23, 2016 at 15:19
Nov 23, 2016 at 14:04 answer added Ivan Izmestiev timeline score: 15
Nov 23, 2016 at 10:32 history asked Kurisuto Asutora CC BY-SA 3.0