Timeline for Fourier transform in terms of special function?
Current License: CC BY-SA 3.0
13 events
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| Nov 24, 2016 at 12:39 | comment | added | Carlo Beenakker |
you need to help Mathematica by telling it that $\lambda>0$, so the full command is Integrate[Cos[1/(3*u^3) + u*lambda^2/4], {u, 0, Infinity}, Assumptions -> lambda > 0] --- on Mathematica 11 that evaluates in terms of these hypergeometric functions.
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| Nov 24, 2016 at 12:18 | comment | added | Châu Trị | I wonder whether it's because I use Mathematica student version that it refuses to compute such integral. | |
| Nov 24, 2016 at 8:05 | comment | added | Carlo Beenakker | there's no "code" really, I just asked Mathematica to ${\tt Integrate}[\cos[1/(3u^3)+u\lambda^2/4,\{u,0,{\tt Infinity}\}]$, and then I massaged the output to make it more compact and systematic. | |
| Nov 24, 2016 at 4:47 | comment | added | Châu Trị | Could you show me the codes please? | |
| Nov 23, 2016 at 14:33 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
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| Nov 23, 2016 at 14:27 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
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| Nov 23, 2016 at 14:20 | history | undeleted | Carlo Beenakker | ||
| Nov 23, 2016 at 14:20 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
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| Nov 23, 2016 at 9:48 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
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| Nov 23, 2016 at 9:45 | history | deleted | Carlo Beenakker | via Vote | |
| Nov 23, 2016 at 9:40 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
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| Nov 23, 2016 at 9:36 | comment | added | Amir Sagiv | To get this result, do you need just straightforward computation, or something more involved? | |
| Nov 23, 2016 at 9:32 | history | answered | Carlo Beenakker | CC BY-SA 3.0 |