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Mar 31, 2022 at 2:41 vote accept Ruy
Mar 25, 2022 at 14:32 answer added Alcides Buss timeline score: 3
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Nov 21, 2016 at 22:51 comment added Ruy I should say that if $A$ is nuclear, then $G$ is indeed exact. This is because the reduced C*-algebra of $G$ will be a subalgebra of the crossed product, which is nuclear as mentioned above.
Nov 21, 2016 at 16:04 history asked Ruy CC BY-SA 3.0