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Nov 20, 2016 at 13:48 vote accept Riccardo
Nov 20, 2016 at 13:07 comment added Denis Nardin @Riccardo Sorry, there were some leftover from the first draft (when I did not realize that we could restrict to finite spectra where the problem is easy). Now it should be better. I also added an explanation of why we can restrict to finite spectra (basically: every homology theory is determined by its restriction to finite spectra, so its operations are too).
Nov 20, 2016 at 13:05 history edited Denis Nardin CC BY-SA 3.0
Removed residues of the first draft; exanded explanation for the AHSS
Nov 20, 2016 at 9:59 comment added Riccardo In the first part of your answer you claim that if $X$ is finite spectrum then all the homology operations comes from a map of spectra, don't you? Because just before you said that you ignore if all of the homology operations "comes from cohomology operations" but then it seems that you prove that all homology operations are of that form.I am "stressing" this point since in the lemma I am referring to $X$ is just any spectrum, not necessarily finite
Nov 20, 2016 at 9:34 comment added Riccardo Thanks Denis, your answer is truly impressive. I will need a little bit of time to meditate on it, but I wanted to thank you as soon as possible!
Nov 20, 2016 at 1:50 history edited Denis Nardin CC BY-SA 3.0
stupid typo spaces→spectra
Nov 20, 2016 at 1:26 history edited Denis Nardin CC BY-SA 3.0
added 147 characters in body
Nov 20, 2016 at 1:21 history edited Denis Nardin CC BY-SA 3.0
added 147 characters in body
Nov 20, 2016 at 1:15 history answered Denis Nardin CC BY-SA 3.0