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Nov 21, 2016 at 17:34 comment added Joe Wells @JeanRaimbault I just noticed your first comment - can you expand upon it a bit? If the two groups are isomorphic (at least, I believe that's what the first sentence in the answer is saying), shouldn't generators for one group map to generators for the other?
Nov 20, 2016 at 12:27 comment added Joe Wells Thank you so much for this very thorough answer. I have some reading to do.
Nov 20, 2016 at 12:26 vote accept Joe Wells
Nov 20, 2016 at 9:52 comment added Jean Raimbault By the way, I don't know what you mean by "wide open" but Swan's algorithm gives a complete solution to finding a finite generating set of a Bianchi group. It's been implemented in Pari by Rahm maths.nuigalway.ie/~rahm/MathematicalSoftware.htm, there is also another algorithm for all arithmetic Kleinian groups in Magma by Page: normalesup.org/~page/Recherche/Logiciels/logiciels-en.html
Nov 20, 2016 at 9:46 comment added Jean Raimbault (1,1)-hermitian forms over $\mathcal O_K$ "parametrise" totally geodesic surfaces in the Bianchi orbifolds, so knowing generators for the latter is not helpful for the original question.
Nov 19, 2016 at 21:56 history edited john mangual CC BY-SA 3.0
link to Ford
Nov 19, 2016 at 21:32 history answered john mangual CC BY-SA 3.0