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Jan 22 at 4:32 comment converted from answer Materia Gravis To correct the calculations given by @Iván, the correct final result should be: $$ \frac{\sigma^2}{2\gamma^3}\left(2\gamma t + 2e^{-\gamma t}+2e^{-\gamma(t+\tau)}-e^{-\gamma \tau}-e^{-\gamma(2t+\tau)}-2 \right) $$
Sep 27, 2023 at 13:47 history edited Michael Hardy CC BY-SA 4.0
added 103 characters in body; edited title
Apr 25, 2022 at 9:30 comment added Quillo See equation (9) here: JOURNAL OF APPLIED MATHEMATICS AND DECISION SCIENCES, 8(1), 1-14 "Three Ways to Solve for Bond Prices in the Vasicek Model", R. S. MAMON ( doi.org/10.1155/S117391260400001X )
Apr 19, 2022 at 12:22 comment added Quillo related: MathSE, math.stackexchange.com/q/4431021/532409
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Nov 28, 2016 at 13:13 vote accept Iván
Nov 18, 2016 at 2:49 history edited Nate Eldredge
edited tags
Nov 18, 2016 at 2:45 answer added Nate Eldredge timeline score: 2
Nov 17, 2016 at 17:13 history edited Iván CC BY-SA 3.0
edited body
Nov 17, 2016 at 17:08 history edited Iván CC BY-SA 3.0
edited body
Nov 17, 2016 at 16:57 history edited Iván CC BY-SA 3.0
t and v are final times and u and s aux times
Nov 17, 2016 at 16:03 comment added Nate Eldredge By the way, I think $s,t,u$ are mixed up in a couple places. You might want to proofread carefully.
Nov 17, 2016 at 16:02 comment added Nate Eldredge Hint: break the double integral into two regions, one with $s \le u$ and the other with $s \ge u$.
Nov 17, 2016 at 15:51 history edited Iván CC BY-SA 3.0
corrected equation
Nov 17, 2016 at 15:47 review First posts
Nov 17, 2016 at 16:32
Nov 17, 2016 at 15:39 history asked Iván CC BY-SA 3.0