Timeline for Can you tie up these Laurent sequences?
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 16, 2016 at 5:43 | comment | added | Pietro Majer | As usually done: square both sides of the relation for the $x_n$, then call $x_n^2=Y_n$, getting a recursion for $Y_n$, which is the one you already have for $y_n$, with the same initial conditions, so $y_n=Y_n$ for all $n$. | |
| Nov 16, 2016 at 5:31 | comment | added | T. Amdeberhan | Can you show how? | |
| Nov 16, 2016 at 5:21 | history | answered | Pietro Majer | CC BY-SA 3.0 |