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Nov 16, 2016 at 14:50 comment added Victor @MichaelBiro This shows how to solve the HAMILTONIAN CYCLE problem (HC), when you know how to solve the Maximum Common Edge Subgraph problem (MCES) (this what I meant by reduction from HC to MCES). But how can you solve MCES (with $G_1$ being a cycle) when you know how to solve HC?
Nov 16, 2016 at 13:01 comment added Michael Biro @Victor Let $G_1$ be a given graph on $n$ vertices and $G_2$ be the $n$ vertex cycle graph. Then $G_1$ has a Hamiltonian cycle if and only if the maximum edge intersection is $n$.
Nov 16, 2016 at 8:25 comment added Victor @BrendanMcKay, thanks for the observation! I cannot see why the HAMILTONIAN CYCLE is a special case of the problem. I see how to reduce the HAMILTONIAN CYCLE to the problem, but does it really coincide with some special case of the problem?
Nov 16, 2016 at 7:45 vote accept Victor
Nov 15, 2016 at 23:22 comment added Brendan McKay In other words, it is NP-hard. Well-known special cases are CLIQUE and HAMILTONIAN CYCLE.
Nov 15, 2016 at 20:44 history answered Michael Biro CC BY-SA 3.0