There is a projection map from $R^2 \setminus (0,0)$ down to this doubled line that simply forgets the y-coordinate except at x = 0. At x = 0 it projects y > 0 to the top origin and y < 0 to the bottom origin.
Using the open cover of the doubled line by two copies of R, one can show that this projection map is a fiber bundle with fiber R. Explicitly, there is a homeomorphism $$ f(x,y) = (x, y/4 - x^2/y) $$$$ f(x,y) = (x, y - x^2/4y) $$ from $R \times (0,\infty)$ to $R^2 \setminus \{y < 0\}$$R^2 \setminus \{(0,y): y \leq 0\}$ with inverse $$ g(x,u) = (x,-2u + 2\sqrt{u^2 + x^2}). $$$$ g(x,u) = (x,(u + \sqrt{u^2 + x^2})/2). $$ (This may look more complicated than it really is; the function f takes the lines $y = c$ and turns them into a sequence of parabolae foliating $R^2 \setminus \{y < 0\}$$R^2 \setminus \{(0,y): y \leq 0\}$.
Thus the map from R2 minus the origin to the doubled line is a weak homotopy equivalence, and so the homotopy groups of the doubled line coincide with those of S1. The fundamental group is ℤ.
Some entertaining generalizations of this include the fact that any finite CW-complex accepts a weak homotopy equivalence to a space with only finitely many points.