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Nov 15, 2016 at 4:34 history edited ABB
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Nov 15, 2016 at 0:41 comment added David Handelman Instead of algebraic, I meant finite-dimensional.
Nov 15, 2016 at 0:27 comment added David Handelman Surely there must be more hypotheses. For example, if $F$ is a subfield of the complexes closed under complex conjugation, then $F$ and all its matrix rings are Baer*. But a positive answer to Q1 for even a single one of these matrix rings forces $F$ to contain square roots of all of its positive elements. So take $F $ to be the rationals, or any algebraic extension thereof (with a complex embedding).
Nov 14, 2016 at 15:12 history asked ABB CC BY-SA 3.0