Timeline for The topology of pointwise convergence with the adjoint operator on a von Neumann algebra
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 13, 2016 at 13:38 | comment | added | clyde | metrisable. Thus continuity is determined on convergent sequences and these are totally bounded. | |
| Nov 13, 2016 at 13:36 | comment | added | clyde | In the separable case, this is true for any of the topologies. This is because continuity is determined on the unit ball which is in each case | |
| Nov 12, 2016 at 18:45 | comment | added | Sergei Akbarov | Clyde, it will take me some time to find these papers. To avoid misunderstandings I want to ask you this: the continuity of a functional $f$ with respect to which of these topologies is equivalent to the continuity of $f$ on totally bounded sets with respect to this topology? | |
| Nov 12, 2016 at 17:57 | comment | added | clyde | I should add that this answers the OP in the case where the underlying Hilbert space is separable since the above topologies are metrisable on the unit ball. I am not sure about what happens in the general case. | |
| Nov 12, 2016 at 17:42 | history | answered | clyde | CC BY-SA 3.0 |