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Dec 1, 2016 at 12:04 answer added Mikhail Katz timeline score: 2
S Nov 21, 2016 at 14:50 history bounty ended CommunityBot
S Nov 21, 2016 at 14:50 history notice removed CommunityBot
Nov 17, 2016 at 18:44 answer added François G. Dorais timeline score: 6
Nov 13, 2016 at 13:51 comment added Todd Trimble Don't really know off-hand; sorry.
Nov 13, 2016 at 13:49 comment added Mikhail Katz @Todd, thanks, that's great. Can one tie in nested sequences of internal sets somehow?
Nov 13, 2016 at 13:44 comment added Todd Trimble Of course compactness theorems in logic are connected to topological compactness. To give a simple example: the main content of compactness for propositional logic is that any Boolean algebra $B$ (e.g., a Lindenbaum algebra of a propositional theory) that is nontrivial (i.e., $0 \neq 1$) admits a Boolean algebra map $\phi: B \to 2$; one can construct a model from this datum $\phi$. This can be inferred from compactness of the Cantor space $2^X$ where $X$ is a set of generators for $B$, and is a starting point of Stone duality. See Prop. 3.1 here: ncatlab.org/nlab/show/Tychonoff+theorem
Nov 13, 2016 at 13:01 comment added Mikhail Katz @JoelDavid, but I don't see an immediate connection between compactness of sets and compactness theorem for first-order logic. Perhaps that's what I should be asking...
Nov 13, 2016 at 12:59 comment added Joel David Hamkins One such unifying idea might be: we can use the compactness theorem of first-order logic to build nonstandard models.
S Nov 13, 2016 at 12:58 history bounty started Mikhail Katz
S Nov 13, 2016 at 12:58 history notice added Mikhail Katz Draw attention
Nov 13, 2016 at 12:56 comment added Mikhail Katz @JoelDavid, obviously this can't be interpreted naively at the level of subsets of $F^\ast$ (for whatever $F$). I was wondering whether perhaps there is an overarching framework where both nesting phenomena would arise as particular manifestations of a common principle. It's really more a question about Los' lemma than nonstandard analysis perhaps, but we don't have a tag for that.
Nov 13, 2016 at 12:51 comment added Joel David Hamkins Yes, of course. My point was that since $\mathbb{Q}^*$ can be saturated, but intervals in $\mathbb{Q}$ are not compact, it may somewhat undermine an expectation of a connection here. (Although your way of stating the principle for nested compact sets is fine for $\mathbb{Q}$.)
Nov 13, 2016 at 12:34 comment added Mikhail Katz @JoelDavid, a nested sequence of internal sets in $\mathbb Z^\ast$ would in particular be a nested sequence of internal sets in $\mathbb R^\ast$ (and any common point would necessarily be a hyperinteger).
Nov 13, 2016 at 11:13 history edited Mikhail Katz CC BY-SA 3.0
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Nov 11, 2016 at 13:26 comment added Joel David Hamkins It's probably worth mentioning also that even the nonstandard rationals $\mathbb{Q}^*$ and the nonstandard integers $\mathbb{Z}^*$ can exhibit countable saturation (and it is possible for all these to be much more saturated than just countably saturated). Meanwhile, saturation is not a consequence of the transfer principle, since one can easily construct nonstandard models lacking saturation. In light of this kind of variation, it's not really correct to speak of the hyperreals.
Nov 11, 2016 at 9:07 history asked Mikhail Katz CC BY-SA 3.0