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Feb 1, 2018 at 17:03 answer added J. van Dobben de Bruyn timeline score: 5
Nov 11, 2016 at 4:23 comment added mrka @NateEldredge I do not know for the answer for the finite dimensional case.
Nov 11, 2016 at 3:14 comment added Nate Eldredge Do you know whether this is true in finite dimensions?
Nov 11, 2016 at 3:05 comment added mrka @NateEldredge, Thank you for the reply. Yes, I would like to work with this definition. I am aware of the result that, self adjoint positive operators on the real Hilbert spaces have unique square roots. Please let me know some references related to this problem.
Nov 10, 2016 at 21:13 comment added Nate Eldredge Your definition of "positive operator" is in some sense not the right one in a real Hilbert space, since it doesn't imply self-adjointness. Are you sure it is the definition you want to work with?
Nov 10, 2016 at 20:30 history edited Pietro Majer CC BY-SA 3.0
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Nov 10, 2016 at 19:21 answer added Nik Weaver timeline score: 2
Nov 10, 2016 at 18:28 review First posts
Nov 10, 2016 at 18:52
Nov 10, 2016 at 18:28 history asked mrka CC BY-SA 3.0