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Nov 10, 2016 at 15:16 comment added Suvrit I think in fact for $n\times n$ matrices, we could get $1/\sqrt{n-1}$ as the multiplicative factor...does that match your simulations?
Nov 10, 2016 at 13:04 comment added Geoff Robinson Maybe the last inequality translates to an easier statement for ${\rm SU}(2,\mathbb{C}).$
Nov 10, 2016 at 11:49 history answered Peter Mueller CC BY-SA 3.0