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Nov 17, 2016 at 15:06 comment added Tom I know that my set has full cardinality and I would be very surprised if it was not Borel, but to be honest, I don't know that yet...
Nov 17, 2016 at 15:04 vote accept Tom
Nov 7, 2016 at 13:25 answer added Carl Mummert timeline score: 9
Nov 7, 2016 at 13:11 comment added Nate Eldredge Is $A$ at least Borel? If you think it might not be Borel, then there is a whole different set of possible techniques to show that (non-measurable, has the wrong cardinality, etc).
Nov 7, 2016 at 12:38 answer added Spirit of Sierpinski timeline score: 9
Nov 7, 2016 at 11:16 history asked Tom CC BY-SA 3.0