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Timeline for Inequality of a concave function

Current License: CC BY-SA 3.0

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Apr 13, 2017 at 12:58 history edited CommunityBot
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Nov 4, 2016 at 16:36 answer added Fedor Petrov timeline score: 2
Nov 4, 2016 at 15:13 comment added CodeGolf @FedorPetrov If $\epsilon=0$, it turns to prove that $G(x)+h(x)(y-x)\ge G(y)$ and taking $h$ to be the derivative of $G$ will work, i.e. $h(x)=G'(x)$.
Nov 4, 2016 at 15:13 comment added CodeGolf @FedorPetrov Thanks a lot for the reply. Indeed, there is a mistake in my question: it should be $h(x)$ instead of $h$. I reformulated the question.
Nov 4, 2016 at 15:12 history edited CodeGolf CC BY-SA 3.0
added 14 characters in body
Nov 4, 2016 at 14:48 comment added Fedor Petrov Say, for $G(x)=-x^2$ such $h$ does not exist (for $x=y=0$ we get $h=0$, but it does not work either.)
Nov 4, 2016 at 14:21 history asked CodeGolf CC BY-SA 3.0