Skip to main content
2 events
when toggle format what by license comment
Oct 31, 2016 at 18:32 comment added Fedor Petrov It is not so awkward. Say, consider the minimal $k$ for which not all the digits from $(8k+1)$-st to $(8k+8)$-th are zeroes. The probability that the dyadic number formed by these 8 digits is divisible by 17 equals $1/17$.
Oct 31, 2016 at 16:23 history answered user83457 CC BY-SA 3.0