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Timeline for Abstract definition of convex set

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Oct 27, 2016 at 19:41 comment added arsmath You need for all $t$ that $(x:t:y) = (x:t:z)$ implies that $y = z$.
Oct 27, 2016 at 19:32 comment added R.. GitHub STOP HELPING ICE In regards to your counterexample, would a requirement that $(x : t_1 : y) \neq (x : t_2 : y)$ unless $x=y$ or $t_1=t_2$, or similar, recover the hope of representation as a vector space?
Oct 27, 2016 at 11:48 vote accept grok
Oct 27, 2016 at 9:57 comment added arsmath There's also an nlab page: ncatlab.org/nlab/show/convex+space They attribute the characterization of barycentric algebra that can be embedded in a vector space (cancellativity) to a 1949 paper of Stone, "Postulates for the barycentric calculus".
Oct 27, 2016 at 9:01 history edited Ben McKay CC BY-SA 3.0
clarified logic
Oct 27, 2016 at 8:20 history answered arsmath CC BY-SA 3.0