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Forgot one condition on (X,d)
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Let $(X,d)$ be a complete separable metric space, and endow $Iso(X,d)$ with the pointwise convergence topology.

I've seen a few sources say this is clearly a Polish group, but why is this this the case?

Let $(X,d)$ be a complete metric space, and endow $Iso(X,d)$ with the pointwise convergence topology.

I've seen a few sources say this is clearly a Polish group, but why is this this the case?

Let $(X,d)$ be a complete separable metric space, and endow $Iso(X,d)$ with the pointwise convergence topology.

I've seen a few sources say this is clearly a Polish group, but why is this this the case?

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Isometry group of a complete separable metric space is Polish?

Let $(X,d)$ be a complete metric space, and endow $Iso(X,d)$ with the pointwise convergence topology.

I've seen a few sources say this is clearly a Polish group, but why is this this the case?