Skip to main content
6 events
when toggle format what by license comment
Oct 24, 2016 at 14:20 history edited Andrea Gagna CC BY-SA 3.0
Added definition of a functor
Oct 23, 2016 at 13:23 comment added Andrea Gagna The functor $\square \to \infty\text{-}\mathcal{C}at$ given by the parity complex is indeed not dense. But apparently its essential image is so! That's nice. Is it true also for the full subcategory of orientals?
Oct 23, 2016 at 12:17 comment added Alexander Campbell Actually the cubes are dense in the category of strict $\infty$-categories (a.k.a. strict $\omega$-categories). This can be used to define the Gray tensor product of strict $\omega$-categories. See section 9 of Street's 'Categorical and combinatorial aspects of descent theory'.
Oct 23, 2016 at 12:05 comment added Edoardo Lanari Cubes are not dense, or (equivalently) the cubical nerve is not fully faithful
Oct 23, 2016 at 10:34 history edited Andrea Gagna CC BY-SA 3.0
added a comment
Oct 22, 2016 at 18:19 history answered Andrea Gagna CC BY-SA 3.0