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Oct 23, 2016 at 17:00 review Close votes
Oct 23, 2016 at 17:45
Oct 23, 2016 at 2:09 comment added George Shakan @NateEldredge Yes of course, I tried to be more clear. I've never seen $f > 0$ mean there exists an x such that $f(x) >0$, so that interpretation wasn't on my radar.
Oct 23, 2016 at 2:07 history edited George Shakan CC BY-SA 3.0
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Oct 22, 2016 at 19:59 comment added Nate Eldredge So, there are incompatible answers based on different interpretations of the question. I read it as asking that the function be $k$ times differentiable on all of $\mathbb{R}$, and the $k$th derivative strictly positive everywhere. Zak, can you edit the question to clarify what you want? Also, the expression $\Delta(g,h)$ defines a function of $x$, if I read it correctly. Are you asking whether $\Delta(f, h_1, \dots, h_k)(x) > 0$ for all $x$, some $x$, etc? And for every $h_1, \dots, h_k > 0$?
Oct 22, 2016 at 18:49 vote accept George Shakan
Oct 22, 2016 at 18:43 vote accept George Shakan
Oct 22, 2016 at 18:45
Oct 22, 2016 at 18:43 comment added Anixx Strictly positive for all x is the first example in my answer.
Oct 22, 2016 at 18:41 vote accept George Shakan
Oct 22, 2016 at 18:43
Oct 22, 2016 at 18:32 comment added Anixx For function $f(x)=10 (1 - \exp(-1/(x + 0.1)^2)) - 9) + \exp(x)$ first 13 derivatives at zero are positive, while the first difference is negative. See my answer.
Oct 22, 2016 at 18:19 vote accept George Shakan
Oct 22, 2016 at 18:41
Oct 22, 2016 at 18:17 vote accept George Shakan
Oct 22, 2016 at 18:19
Oct 22, 2016 at 17:59 answer added Anixx timeline score: 1
Oct 22, 2016 at 17:53 answer added Fedor Petrov timeline score: 6
Oct 22, 2016 at 17:46 history asked George Shakan CC BY-SA 3.0