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Oct 22, 2016 at 13:28 comment added Mare it can be found in the book of skowronski and yamgata "frobenius algebras I" somewhere I think. It is also not hard to see it via Morita theory.
Oct 22, 2016 at 13:26 comment added Xiaosong Peng @Mare Hello, sir. I don't know this result " two algebras over an algebraically closed field are Morita equivalent iff their quiver algebras are isomorphic", could you tell me where to find it?
Oct 22, 2016 at 13:22 vote accept Xiaosong Peng
Oct 22, 2016 at 13:18 comment added Mare no, but to get the necessary information you just need a resolution of a module which contains every indecomposable projective module (and just such modules) as a direct summand and this is the case.
Oct 22, 2016 at 13:16 comment added Xiaosong Peng @Mare For question 2), I know that Morita equivalence holds these properties. But given a minimal injective resolution of $A$, can you make sure the equivalence maps $A$ to $B$?
Oct 22, 2016 at 13:13 comment added Mare It is not really easy, I should have said "easy, compared to check derived equivalence".
Oct 22, 2016 at 13:12 comment added Benjamin Steinberg How easy is it really to compute a quiver presentation from say structure constants for the algebra? There are very few monoid algebras for which I know how to do it.
Oct 22, 2016 at 13:09 history answered Mare CC BY-SA 3.0