Timeline for Do you know how to construct a compact hyperbolic 3-manifold with three or four totally geodesic boundary components?
Current License: CC BY-SA 2.5
5 events
| when toggle format | what | by | license | comment | |
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| May 20, 2010 at 0:41 | comment | added | HJRW | Yes, there are lots of ways to be more concrete. Another would be to look at congruence covers. | |
| May 19, 2010 at 22:44 | vote | accept | b b | ||
| May 19, 2010 at 21:59 | comment | added | Matthew Stover | You can be more explicit if you pick something with one boundary component and $\mathbb Z$ homology not coming from the boundary. For example, take a closed hyperbolic 3-manifold with a totally geodesic separating surface that doesn't carry all the homology, and cut the closed manifold in half. (Okay, and make sure there's homology supported on one half.) Pull-back from $\mathbb Z / n \mathbb Z$ quotients from that homology, and you get your covers with $n$ boundary components. | |
| May 19, 2010 at 21:49 | history | edited | HJRW | CC BY-SA 2.5 |
added 261 characters in body
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| May 19, 2010 at 20:53 | history | answered | HJRW | CC BY-SA 2.5 |