Skip to main content
6 events
when toggle format what by license comment
May 19, 2010 at 22:36 answer added KConrad timeline score: 29
May 19, 2010 at 22:08 comment added Dror Speiser Another reference: "Introduction to Cyclotomic Fields", L. C. Washington, pp 45, exercise 4.5.
May 19, 2010 at 22:07 comment added Will Jagy Note that this is trivial for $p \equiv 1 \pmod 4$ because then $-1$ is a quadratic residue, and any $k$ is a quadratic residue if and only if $p-k$ is. So exactly half lie in your interval, exactly half lie in the interval from $(p+1)/2$ to $p-1.$
May 19, 2010 at 20:45 vote accept Andrea Ferretti
May 19, 2010 at 19:17 answer added Cam McLeman timeline score: 13
May 19, 2010 at 18:43 history asked Andrea Ferretti CC BY-SA 2.5