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So firstly, you need to compactify $M(2)$ to get $\mathbb{P}^1_{\mathbb{Z}[1/2]}$. Once you do, the answers to your question here:

Modular curve X(2)

imply that $\overline{M(2)}_{\mathbb{Q}}\cong\mathbb{P}^1_\mathbb{Q}$. On the other hand by general nonsense, $\overline{M(2)}$ is a smooth scheme over $\mathbb{Z}[1/2]$, and hence all fibers are geometrically of genus 0.

Now, to prove that it's actually $\mathbb{P}^1_{\mathbb{Z}[1/2]}$, I believe it should suffice to produce enough distinct sections on $\overline{M(2)}$ (I think 3 should be enough, though maybe in this case 1 is enough?)

To do this, it suffices to look at the 3 cusps, which correspond via the Deligne-Rapoport compactification to the three nonisomorphic $\Gamma(2)$-structures on a Neron 2-gon. These three $\Gamma(2)$-structures are defined over $\mathbb{Z}[1/2]$, and are not geometrically isomorphic over any prime $p\ne 2$, and hence the three cuspidal sections do not intersect over any prime $p\ne 2$. This shows that all fibers of $\overline{M(2)}$ are isomorphic to $\mathbb{P}^1$ over the residue field, and my intuition is that the existence of these three sections serve to "rigidify the deformation problem" (or something) to guarantee that the surface is indeed just $\mathbb{P}^1_{\mathbb{Z}[1/2]}$ (I would be grateful if someone could elaborate on this)

Remark: Note that we can always produce a non-cuspidal section, namely, the elliptic curve $$E : y^2 = x^3-x$$ which has discriminant $\Delta = 64$, and hence defines an elliptic curve over $\mathbb{Z}[1/2]$, together with the points $(0,0),(1,0)$ which define a $\Gamma(2)$-structure on $E$ over $\mathbb{Z}[1/2]$. This section together with the 3 cuspidal sections never intersect over any prime $p\ne 2$, and indeed forms a maximal set of nonintersecting sections, since at $p = 3$, $\mathbb{P}^1_{\mathbb{F}_3}$ only has four $\mathbb{F}_3$-rational points!

Appendix: A Neron $n$-gon is a chain of $n$ copies of $\mathbb{P}^1$'s, where $0$ in one copy is glued to $\infty$ in the next copy. A Neron 1-gon is just a nodal cubic. The smooth locus of an $n$-gon is isomorphic to $\mathbb{G}_m\times\mathbb{Z}/n\mathbb{Z}$, and is equipped with the obvious group structure, where $\mathbb{Z}/n\mathbb{Z}$ is viewed as a constant group scheme. It's $n$-torsion is thus just $\mu_n\times\mathbb{Z}/n\mathbb{Z}$. For $n = 2$, we find that over $\mathbb{Z}[1/2]$, its 2-torsion is $\mu_2\times\mathbb{Z}/2\mathbb{Z}$, which is completely decomposed as a finite etale group scheme over $\mathbb{Z}[1/2]$, and thus admits three nonisomorphic bases (ie, three nonisomorphic $\Gamma(2)$-structures), each of which corresponds to a cuspidal section of $\overline{M(2)}$.

So firstly, you need to compactify $M(2)$ to get $\mathbb{P}^1_{\mathbb{Z}[1/2]}$. Once you do, the answers to your question here:

Modular curve X(2)

imply that $\overline{M(2)}_{\mathbb{Q}}\cong\mathbb{P}^1_\mathbb{Q}$. On the other hand by general nonsense, $\overline{M(2)}$ is a smooth scheme over $\mathbb{Z}[1/2]$, and hence all fibers are geometrically of genus 0.

Now, to prove that it's actually $\mathbb{P}^1_{\mathbb{Z}[1/2]}$, I believe it should suffice to produce enough distinct sections on $\overline{M(2)}$ (I think 3 should be enough, though maybe in this case 1 is enough?)

To do this, it suffices to look at the 3 cusps, which correspond via the Deligne-Rapoport compactification to the three nonisomorphic $\Gamma(2)$-structures on a Neron 2-gon. These three $\Gamma(2)$-structures are defined over $\mathbb{Z}[1/2]$, and are not geometrically isomorphic over any prime $p\ne 2$, and hence the three cuspidal sections do not intersect over any prime $p\ne 2$. This shows that all fibers of $\overline{M(2)}$ are isomorphic to $\mathbb{P}^1$ over the residue field, and my intuition is that the existence of these three sections serve to "rigidify the deformation problem" (or something) to guarantee that the surface is indeed just $\mathbb{P}^1_{\mathbb{Z}[1/2]}$ (I would be grateful if someone could elaborate on this)

Remark: Note that we can always produce a non-cuspidal section, namely, the elliptic curve $$E : y^2 = x^3-x$$ which has discriminant $\Delta = 64$, and hence defines an elliptic curve over $\mathbb{Z}[1/2]$, together with the points $(0,0),(1,0)$ which define a $\Gamma(2)$-structure on $E$ over $\mathbb{Z}[1/2]$. This section together with the 3 cuspidal sections never intersect over any prime $p\ne 2$, and indeed forms a maximal set of nonintersecting sections, since at $p = 3$, $\mathbb{P}^1_{\mathbb{F}_3}$ only has four $\mathbb{F}_3$-rational points!

Appendix: A Neron $n$-gon is a chain of $n$ copies of $\mathbb{P}^1$'s, where $0$ in one copy is glued to $\infty$ in the next copy. A Neron 1-gon is just a nodal cubic. The smooth locus of an $n$-gon is isomorphic to $\mathbb{G}_m\times\mathbb{Z}/n\mathbb{Z}$, and is equipped with the obvious group structure, where $\mathbb{Z}/n\mathbb{Z}$ is viewed as a constant group scheme. It's $n$-torsion is thus just $\mu_n\times\mathbb{Z}/n\mathbb{Z}$. For $n = 2$, we find that over $\mathbb{Z}[1/2]$, its 2-torsion is $\mu_2\times\mathbb{Z}/2\mathbb{Z}$, which is completely decomposed as a finite etale group scheme over $\mathbb{Z}[1/2]$, and thus admits three nonisomorphic bases (ie, three nonisomorphic $\Gamma(2)$-structures), each of which corresponds to a cuspidal section of $\overline{M(2)}$.

So firstly, you need to compactify $M(2)$ to get $\mathbb{P}^1_{\mathbb{Z}[1/2]}$. Once you do, the answers to your question here:

Modular curve X(2)

imply that $\overline{M(2)}_{\mathbb{Q}}\cong\mathbb{P}^1_\mathbb{Q}$. On the other hand by general nonsense, $\overline{M(2)}$ is a smooth scheme over $\mathbb{Z}[1/2]$, and hence all fibers are geometrically of genus 0.

Now, to prove that it's actually $\mathbb{P}^1_{\mathbb{Z}[1/2]}$, I believe it should suffice to produce enough distinct sections on $\overline{M(2)}$ (I think 3 should be enough, though maybe in this case 1 is enough?)

To do this, it suffices to look at the 3 cusps, which correspond via the Deligne-Rapoport compactification to the three nonisomorphic $\Gamma(2)$-structures on a Neron 2-gon. These three $\Gamma(2)$-structures are defined over $\mathbb{Z}[1/2]$, and are not geometrically isomorphic over any prime $p\ne 2$, and hence the three cuspidal sections do not intersect over any prime $p\ne 2$. This shows that all fibers of $\overline{M(2)}$ are isomorphic to $\mathbb{P}^1$ over the residue field, and my intuition is that the existence of these three sections serve to "rigidify the deformation problem" (or something) to guarantee that the surface is indeed just $\mathbb{P}^1_{\mathbb{Z}}$ (I would be grateful if someone could elaborate on this)

Remark: Note that we can always produce a non-cuspidal section, namely, the elliptic curve $$E : y^2 = x^3-x$$ which has discriminant $\Delta = 64$, and hence defines an elliptic curve over $\mathbb{Z}[1/2]$, together with the points $(0,0),(1,0)$ which define a $\Gamma(2)$-structure on $E$ over $\mathbb{Z}[1/2]$. This section together with the 3 cuspidal sections never intersect over any prime $p\ne 2$, and indeed forms a maximal set of nonintersecting sections, since at $p = 3$, $\mathbb{P}^1_{\mathbb{F}_3}$ only has four $\mathbb{F}_3$-rational points!

Appendix: A Neron $n$-gon is a chain of $n$ copies of $\mathbb{P}^1$'s, where $0$ in one copy is glued to $\infty$ in the next copy. A Neron 1-gon is just a nodal cubic. The smooth locus of an $n$-gon is isomorphic to $\mathbb{G}_m\times\mathbb{Z}/n\mathbb{Z}$, and is equipped with the obvious group structure, where $\mathbb{Z}/n\mathbb{Z}$ is viewed as a constant group scheme. It's $n$-torsion is thus just $\mu_n\times\mathbb{Z}/n\mathbb{Z}$. For $n = 2$, we find that over $\mathbb{Z}[1/2]$, its 2-torsion is $\mu_2\times\mathbb{Z}/2\mathbb{Z}$, which is completely decomposed as a finite etale group scheme over $\mathbb{Z}[1/2]$, and thus admits three nonisomorphic bases (ie, three nonisomorphic $\Gamma(2)$-structures), each of which corresponds to a cuspidal section of $\overline{M(2)}$.

So firstly, you need to compactify $M(2)$ to get $\mathbb{P}^1_{\mathbb{Z}[1/2]}$. Once you do, the answers to your question here:

Modular curve X(2)

imply that $\overline{M(2)}_{\mathbb{Q}}\cong\mathbb{P}^1_\mathbb{Q}$. On the other hand by general nonsense, $\overline{M(2)}$ is a smooth scheme over $\mathbb{Z}[1/2]$, and hence all fibers are geometrically of genus 0.

Now, to prove that it's actually $\mathbb{P}^1_{\mathbb{Z}[1/2]}$, I believe it should suffice to produce enough distinct sections on $\overline{M(2)}$ (I think 3 should be enough, though maybe in this case 1 is enough?)

To do this, it suffices to look at the 3 cusps, which correspond via the Deligne-Rapoport compactification to the three nonisomorphic $\Gamma(2)$-structures on a Neron 2-gon. These three $\Gamma(2)$-structures are defined over $\mathbb{Z}[1/2]$, and are not geometrically isomorphic over any prime $p\ne 2$, and hence the three cuspidal sections do not intersect over any prime $p\ne 2$. This shows that all fibers of $\overline{M(2)}$ are isomorphic to $\mathbb{P}^1$ over the residue field, and my intuition is that the existence of these three sections serve to "rigidify the deformation problem" (or something) to guarantee that the surface is indeed just $\mathbb{P}^1_{\mathbb{Z}[1/2]}$ (I would be grateful if someone could elaborate on this)

Remark: Note that we can always produce a non-cuspidal section, namely, the elliptic curve $$E : y^2 = x^3-x$$ which has discriminant $\Delta = 64$, and hence defines an elliptic curve over $\mathbb{Z}[1/2]$, together with the points $(0,0),(1,0)$ which define a $\Gamma(2)$-structure on $E$ over $\mathbb{Z}[1/2]$. This section together with the 3 cuspidal sections never intersect over any prime $p\ne 2$, and indeed forms a maximal set of nonintersecting sections, since at $p = 3$, $\mathbb{P}^1_{\mathbb{F}_3}$ only has four $\mathbb{F}_3$-rational points!

Appendix: A Neron $n$-gon is a chain of $n$ copies of $\mathbb{P}^1$'s, where $0$ in one copy is glued to $\infty$ in the next copy. A Neron 1-gon is just a nodal cubic. The smooth locus of an $n$-gon is isomorphic to $\mathbb{G}_m\times\mathbb{Z}/n\mathbb{Z}$, and is equipped with the obvious group structure, where $\mathbb{Z}/n\mathbb{Z}$ is viewed as a constant group scheme. It's $n$-torsion is thus just $\mu_n\times\mathbb{Z}/n\mathbb{Z}$. For $n = 2$, we find that over $\mathbb{Z}[1/2]$, its 2-torsion is $\mu_2\times\mathbb{Z}/2\mathbb{Z}$, which is completely decomposed as a finite etale group scheme over $\mathbb{Z}[1/2]$, and thus admits three nonisomorphic bases (ie, three nonisomorphic $\Gamma(2)$-structures), each of which corresponds to a cuspidal section of $\overline{M(2)}$.

So firstly, you need to compactify $M(2)$ to get $\mathbb{P}^1_{\mathbb{Z}[1/2]}$. Once you do, the answers to your question here:

Modular curve X(2)

imply that $\overline{M(2)}_{\mathbb{Q}}\cong\mathbb{P}^1_\mathbb{Q}$. On the other hand by general nonsense, $\overline{M(2)}$ is a smooth scheme over $\mathbb{Z}[1/2]$, and hence all fibers are geometrically of genus 0.

Now, to prove that it's actually $\mathbb{P}^1_{\mathbb{Z}[1/2]}$, I believe it should suffice to produce enough distinct sections on $\overline{M(2)}$ (I think 3 should be enough, though maybe in this case 1 is enough?)

To do this, it suffices to look at the 3 cusps, which correspond via the Deligne-Rapoport compactification to the three nonisomorphic $\Gamma(2)$-structures on a Neron 2-gon. These three $\Gamma(2)$-structures are defined over $\mathbb{Z}[1/2]$, and are not geometrically isomorphic over any prime $p\ne 2$, and hence the three cuspidal sections do not intersect over any prime $p\ne 2$. This shows that all fibers of $\overline{M(2)}$ are isomorphic to $\mathbb{P}^1$ over the residue field, and my intuition is that the existence of these three sections serve to "rigidify the deformation problem" (or something) to guarantee that the surface is indeed just $\mathbb{P}^1_{\mathbb{Z}}$ (I would be grateful if someone could elaborate on this)

Remark: Note that we can always produce a non-cuspidal section, namely, the elliptic curve $$E : y^2 = x^3-x$$ which has discriminant $\Delta = 64$, and hence defines an elliptic curve over $\mathbb{Z}[1/2]$, together with the points $(0,0),(1,0)$ which define a $\Gamma(2)$-structure on $E/\mathbb{Z}[1/2]$. This section together with the 3 cuspidal sections never intersect over any prime $p\ne 2$, and indeed forms a maximal set of nonintersecting sections, since at $p = 3$, $\mathbb{P}^1_{\mathbb{F}_3}$ only has four $\mathbb{F}_3$-rational points!

So firstly, you need to compactify $M(2)$ to get $\mathbb{P}^1_{\mathbb{Z}[1/2]}$. Once you do, the answers to your question here:

Modular curve X(2)

imply that $\overline{M(2)}_{\mathbb{Q}}\cong\mathbb{P}^1_\mathbb{Q}$. On the other hand by general nonsense, $\overline{M(2)}$ is a smooth scheme over $\mathbb{Z}[1/2]$, and hence all fibers are geometrically of genus 0.

Now, to prove that it's actually $\mathbb{P}^1_{\mathbb{Z}[1/2]}$, I believe it should suffice to produce enough distinct sections on $\overline{M(2)}$ (I think 3 should be enough, though maybe in this case 1 is enough?)

To do this, it suffices to look at the 3 cusps, which correspond via the Deligne-Rapoport compactification to the three nonisomorphic $\Gamma(2)$-structures on a Neron 2-gon. These three $\Gamma(2)$-structures are defined over $\mathbb{Z}[1/2]$, and are not geometrically isomorphic over any prime $p\ne 2$, and hence the three cuspidal sections do not intersect over any prime $p\ne 2$. This shows that all fibers of $\overline{M(2)}$ are isomorphic to $\mathbb{P}^1$ over the residue field, and my intuition is that the existence of these three sections serve to "rigidify the deformation problem" (or something) to guarantee that the surface is indeed just $\mathbb{P}^1_{\mathbb{Z}}$ (I would be grateful if someone could elaborate on this)

Remark: Note that we can always produce a non-cuspidal section, namely, the elliptic curve $$E : y^2 = x^3-x$$ which has discriminant $\Delta = 64$, and hence defines an elliptic curve over $\mathbb{Z}[1/2]$, together with the points $(0,0),(1,0)$ which define a $\Gamma(2)$-structure on $E$ over $\mathbb{Z}[1/2]$. This section together with the 3 cuspidal sections never intersect over any prime $p\ne 2$, and indeed forms a maximal set of nonintersecting sections, since at $p = 3$, $\mathbb{P}^1_{\mathbb{F}_3}$ only has four $\mathbb{F}_3$-rational points!

Appendix: A Neron $n$-gon is a chain of $n$ copies of $\mathbb{P}^1$'s, where $0$ in one copy is glued to $\infty$ in the next copy. A Neron 1-gon is just a nodal cubic. The smooth locus of an $n$-gon is isomorphic to $\mathbb{G}_m\times\mathbb{Z}/n\mathbb{Z}$, and is equipped with the obvious group structure, where $\mathbb{Z}/n\mathbb{Z}$ is viewed as a constant group scheme. It's $n$-torsion is thus just $\mu_n\times\mathbb{Z}/n\mathbb{Z}$. For $n = 2$, we find that over $\mathbb{Z}[1/2]$, its 2-torsion is $\mu_2\times\mathbb{Z}/2\mathbb{Z}$, which is completely decomposed as a finite etale group scheme over $\mathbb{Z}[1/2]$, and thus admits three nonisomorphic bases (ie, three nonisomorphic $\Gamma(2)$-structures), each of which corresponds to a cuspidal section of $\overline{M(2)}$.