Skip to main content
9 events
when toggle format what by license comment
Apr 13, 2017 at 12:19 history edited CommunityBot
replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
Oct 20, 2016 at 14:14 vote accept Arrow
Oct 19, 2016 at 14:46 history edited Arrow CC BY-SA 3.0
added 238 characters in body; edited title
Oct 19, 2016 at 13:39 comment added მამუკა ჯიბლაძე @SimonHenry Right, I now realized there indeed are such examples. Probably the simplest one is in $\mathbb Z/2\mathbb Z$-sets. A two element set with a nontrivial involution has underlying set isomorphic to that of $\Omega$ but the latter has a trivial action. Presumably there also exist simple localic examples.
Oct 19, 2016 at 12:43 comment added Simon Henry Well you can start with a $F$ that is indeed a subobject of $\Omega$ and then mix every $F(X)$ by some chosen automorphism of $\Omega(X)$ for each $X$. You end up with $F(X)$ being identified with a subset of $\Omega(X)$ for all $X$ but not in a way compatible to functoriality.I'm not sure how to construct an example where it is not possible to make the map agree by changing the maps $F(X) \rightarrow \Omega(X)$ but I don't see any reasons for this not being possible
Oct 19, 2016 at 12:28 comment added მამუკა ჯიბლაძე @SimonHenry What would be a counterexample? That is, a sheaf $F$ with $F(X)\subseteq\operatorname{Sub}(X)$ for all $X$ but induced maps on $F$ not agreeing with those of $\operatorname{Sub}$? And can it happen that $F$ is not even isomorphic to one with agreeing induced maps?
Oct 19, 2016 at 11:30 answer added Simon Henry timeline score: 3
Oct 18, 2016 at 23:48 comment added Simon Henry A first remark: You also need to add this assumption that for every morphism $f :X \rightarrow Y$ the induced morphism $F(Y) \rightarrow F(X)$ corresponds to the pullback when you identify element of $F(X)$ and $F(Y)$ with subobjects of $X$ and $Y$ to deduce that $F$ is a subobject of $\Omega$. For the rest of the question, this is more subtle: roughly being a frame internally imply being a frame on each object, but being a frame internally is considerably stronger (see the famous "An Extension of the Galois Theory of Grothendieck") I'll think more about it tomorrow
Oct 18, 2016 at 23:12 history asked Arrow CC BY-SA 3.0