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Oct 21, 2016 at 23:09 comment added Elena Yudovina Since the Ito martingale is an isometry, this is equivalent to asking whether $\|\Phi^\varsigma-\Phi\| \to 0$ as $|\varsigma| \to 0$, for mean-square-discontinuous $\Phi \in \overline{\mathcal E}$. It seems that the answer should be no, by letting $t$ be a point of mean-square-discontinuity of $\Phi$, and a sequence of partitions $\varsigma$ in which $t$ is always one of the points picked.
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