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Mar 11, 2019 at 22:45 vote accept Wojowu
May 8, 2018 at 5:50 answer added user19475 timeline score: 0
May 8, 2018 at 5:23 history edited Lucia
added top level tag
May 8, 2018 at 5:23 answer added Lucia timeline score: 9
May 8, 2018 at 4:46 comment added user19475 Every finite abelian group is an $S$-class group of some number field. I don't remember the reference.
May 8, 2018 at 4:33 answer added silvascientist timeline score: 0
Oct 16, 2016 at 22:04 comment added Gerry Myerson The system does not allow closing a question on one site as a duplicate of a question on a different site. One option, Wojowu, is for you to post an answer here, summarizing what's over there, and linking to it, and then accept your answer.
Oct 16, 2016 at 20:39 comment added Wojowu @FranzLemmermeyer Thanks, I haven't seen that question when searching about the topic. I suppose at this point my question can be closed.
Oct 16, 2016 at 20:36 comment added Franz Lemmermeyer duplicate: math.stackexchange.com/questions/10949/…
Oct 16, 2016 at 19:55 comment added Wojowu @StevenLandsburg I was not aware of that result, since, to be honest, I am not so interested in general Dedekind's domain. I will definitely take a look at this result though.
Oct 16, 2016 at 19:52 comment added Steven Landsburg Not an answer to your question, but are you aware of Claborn's theorem that says every finite abelian group is the class group of a Dedekind domain (though not necessarily, as far as one can tell from Claborn's work, of a ring of integers)?
Oct 16, 2016 at 19:48 history asked Wojowu CC BY-SA 3.0