Timeline for What is a Fermi surface?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 16, 2016 at 22:15 | comment | added | Minhyong Kim | I've finally looked into Ashcroft and Mermin and deciphered that 'band' there just refers to an energy level. | |
| Oct 14, 2016 at 17:25 | comment | added | Minhyong Kim | Or perhaps it's that each band is actually quite thin, so that the equation defines 'essentially a surface'? | |
| Oct 14, 2016 at 17:22 | comment | added | Francois Ziegler | @MinhyongKim Yes, I think that's it. (Several surfaces, or as they put it, one surface with several "branches". Of course, not all $n$ will enter for a given $\mathcal E_F$.) | |
| Oct 14, 2016 at 17:21 | comment | added | Minhyong Kim | Ah, I see. So there is a surface for each energy level, not just for each band? | |
| Oct 14, 2016 at 17:18 | comment | added | Francois Ziegler | @MinhyongKim I believe this is answered by the edit I was making while you asked. There is a different eigenvalue problem for each $\mathbf k$, and $\mathcal E_n(\mathbf k)$ is its $n$-th eigenvalue. | |
| Oct 14, 2016 at 17:14 | comment | added | Minhyong Kim | Many thanks. This is very helpful. However, I'm still confused by one thing. For the equation you write to define a surface in $k$-space, $ E_n(k)$ would have to be a *function of $k $*. However, if $n$ is an index for the band, each band is made up of many energy levels. So which level goes into the equation? | |
| Oct 14, 2016 at 17:11 | history | edited | Francois Ziegler | CC BY-SA 3.0 |
added 894 characters in body
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| Oct 14, 2016 at 16:52 | history | answered | Francois Ziegler | CC BY-SA 3.0 |