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May 13, 2018 at 0:13 vote accept toshi
Oct 26, 2016 at 23:01 comment added GH from MO @user1952009: Thanks for your kind words. I think downvoting should have a serious reason. But let me upvote you! :-)
Oct 26, 2016 at 21:37 comment added reuns :) you are allowed to downvote me anyway, you teached me many things
Oct 26, 2016 at 21:32 comment added GH from MO @user1952009: No, I did not downvote.
Oct 26, 2016 at 21:15 comment added reuns @GHfromMO I wanted to know if you disapproved too, tks (I have some difficulties proving how to make $\sum_\beta \frac{x^\beta}{\beta L'(\beta,\chi)}$ convergent)
Oct 26, 2016 at 21:08 comment added GH from MO @user1952009: I don't know for sure. Usually, technical responses get fewer upvotes, and also users who have been around for longer get more upvotes and less downvotes. Your response is a bit technical, e.g. it does not reveal what can be said under the RH, or a weaker RH, or unconditionally (as in my response). Instead, it provides some intermediate information that could leave to certain bounds, but the OP wanted the bounds themselves. Finally, giving yourself a decent username (instead of "user" plus some number) would help in my opinion. Just my two cents.
Oct 26, 2016 at 20:41 comment added reuns @GHfromMO do you have an idea why my answer is dis-approved ?
Oct 14, 2016 at 21:15 comment added GH from MO @toshi: Well, the constant $c>0$ can be calculated explicitly (and I guess it has been done, but I don't know for sure), while the implied constant is ineffective for any $A>2$ as it comes from Siegel's theorem on Siegel zeros. I don't think there is any effective result for any $A>2$.
Oct 14, 2016 at 20:05 comment added toshi Yes, you're correct, I have forgotten to put that I need it in an explicit form.
Oct 14, 2016 at 15:35 history edited GH from MO CC BY-SA 3.0
added 174 characters in body
Oct 14, 2016 at 15:29 history answered GH from MO CC BY-SA 3.0