Skip to main content
9 events
when toggle format what by license comment
Oct 13, 2016 at 18:55 vote accept Ali Taghavi
Oct 10, 2016 at 12:13 answer added Simon Henry timeline score: 1
Oct 10, 2016 at 9:52 comment added Simon Henry If I'm not mistaken, the groupoid you obtain is equivalent to the free group on $(n-2)(n-1)/2$ generators. So this algebra you obtain should be isomorphic (possibly non canonically) to something like the algebra of $n$ by $n$ matrix with coefficient in the algebra of the free group on $(n-2)(n-1)/2$ generators.
Oct 10, 2016 at 9:36 comment added Simon Henry What do you cal the "groupoid associated with this semi-group" ? The localization at all arrows ? (i.e. the groupoid obtained by formally inverting all arrow) If so I really don't think the $C^*$-algebra you will obtain will be finite dimensional... Unless you have a reason to say it will be that I missed ?
Oct 10, 2016 at 8:07 history edited Ali Taghavi CC BY-SA 3.0
added 71 characters in body
Oct 9, 2016 at 20:34 comment added Uri Bader You will probably end up having $\text{Mor}(x,y)$ being the full free abelain group generated by $X$ for all $x,y$.
Oct 9, 2016 at 20:23 history edited Ali Taghavi CC BY-SA 3.0
edited body
Oct 9, 2016 at 20:02 history edited Ali Taghavi CC BY-SA 3.0
added 3 characters in body
Oct 9, 2016 at 19:51 history asked Ali Taghavi CC BY-SA 3.0