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Oct 9, 2016 at 14:48 comment added Paata Ivanishvili What about Brunn-Minkowski inequality but with essential minkowski sum? In this case $A+_{e}B=\{z \in \mathbb{R}^{n} : \mu(A \cap (\{z\}-B))\neq 0\}$. Clearly if $A$ or $B$ has $n$ dimensional Lebesgue measure zero then always $\mu(A \cap (\{z\}-B))=0$, and aessential minkowsi sum does not give you anything. So then we have just equality $| A+_{e}B|^{1/n}\geq |A|^{1/n}+|B|^{1/n}$ instead of inequality. The same thing with Prekopa--Leindler but with essential supremum. (see the last section en.wikipedia.org/wiki/Minkowski_addition)
Oct 9, 2016 at 6:16 answer added Ivan Izmestiev timeline score: 1
Oct 9, 2016 at 5:10 answer added T. Amdeberhan timeline score: 0
Oct 9, 2016 at 4:36 history asked SorcererofDM CC BY-SA 3.0