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May 19, 2010 at 14:40 comment added Gerald Edgar @Colin: I prefer to say not that the domain is fractal, but the boundary is. And that biholomorphism generally is not Lipschitz on the boundary.
May 19, 2010 at 3:06 comment added user2529 for instance any simply connected proper domain of the plane (which could be a fractal) is biholomorphic to the open disc (which is not a fractal). but yet biholomorphism implies homeomorphism.
May 19, 2010 at 3:01 comment added user2529 thanks edgar. and all these definitions of dimension are invariant under isometry/hemeomorphism?
May 19, 2010 at 3:01 vote accept CommunityBot
May 18, 2010 at 14:07 history answered Gerald Edgar CC BY-SA 2.5