Timeline for An elementary proof for a limit?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 2, 2016 at 13:03 | comment | added | T. Amdeberhan | You are right, Fedor. | |
| Oct 2, 2016 at 13:01 | comment | added | Fedor Petrov | I need both $t=x/y, t=y/x$. And your $t$ is my $t-1$, even worse. | |
| Oct 2, 2016 at 6:07 | comment | added | Fedor Petrov | The last inequality fails for $t<1$. | |
| Oct 2, 2016 at 2:46 | vote | accept | T. Amdeberhan | ||
| Oct 2, 2016 at 2:05 | comment | added | T. Amdeberhan | Yes, we may assume we know $\log t<t-1$ because iff $\log(1+t)<t$ iff $1+t<e^t$ iff $e^t>2^t=(1+1)^t>1+t$ from Binomial Theorem. | |
| Oct 1, 2016 at 22:57 | history | edited | Fedor Petrov | CC BY-SA 3.0 |
added 537 characters in body
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| Oct 1, 2016 at 22:41 | comment | added | T. Amdeberhan | This is cool, Fedor. Yet, we're using a tool (derivatives) which is an equivalent for integrals (as you noted). Is it possible to stay away from both (sorry I was not very clear) and apply only ideas of sequences, such as Cauchy and basic limit theorems for sequences? | |
| Oct 1, 2016 at 22:21 | history | answered | Fedor Petrov | CC BY-SA 3.0 |