Timeline for Short map between hyperbolic triangles
Current License: CC BY-SA 3.0
13 events
when toggle format | what | by | license | comment | |
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Nov 16, 2016 at 16:06 | answer | added | FMB | timeline score: 1 | |
S Sep 29, 2016 at 13:48 | history | suggested | Ivan Izmestiev | CC BY-SA 3.0 |
Some grammar, exchanging T' and T, streamlining a bit (not mentioning the space M). Changing the vertex notation.
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Sep 29, 2016 at 12:57 | review | Suggested edits | |||
S Sep 29, 2016 at 13:48 | |||||
Sep 28, 2016 at 15:37 | vote | accept | FMB | ||
Sep 28, 2016 at 14:03 | answer | added | Ivan Izmestiev | timeline score: 5 | |
Sep 28, 2016 at 13:33 | comment | added | Ivan Izmestiev | Note that domination for small enough $\epsilon$ implies domination for all $\epsilon$. | |
Sep 28, 2016 at 12:54 | comment | added | Neal | Perhaps try working in barycentric coordinates using metric pulled back from the Klein model. | |
Sep 28, 2016 at 12:26 | history | edited | FMB | CC BY-SA 3.0 |
edited title
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Sep 28, 2016 at 11:24 | comment | added | FMB | This is what I did for the Euclidian case, but the calculation of the derivatives for the hyperbolic gives messy formulas involving hyperbolic sines and cosines that I was unable to manipulate. | |
Sep 28, 2016 at 11:19 | comment | added | Ivan Izmestiev | Can you compute the derivative with respect to $\epsilon$ of the distance between pairs of corresponding points (could be easier than comparing distances)? | |
Sep 28, 2016 at 11:16 | comment | added | FMB | Yes, the map is only defined on the boundary. If we know it is a short map we can extend it to the interior of the triangle with the Kirszbraun theorem. | |
Sep 28, 2016 at 11:12 | comment | added | Ivan Izmestiev | Your map is between the boundaries of the triangles, and not defined in the interior, right? | |
Sep 28, 2016 at 10:13 | history | asked | FMB | CC BY-SA 3.0 |