Timeline for How to prove that $\sum_{i=0}^n\frac{(a;q)_i}{(q;q)_i}\frac{(b;q)_{n-i}}{(q;q)_{n-i}}a^{n-i}=\frac{(ab;q)_n}{(q;q)_n}$?
Current License: CC BY-SA 3.0
2 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 23, 2017 at 14:28 | vote | accept | Frank Z.K. Li | ||
| Sep 25, 2016 at 19:31 | history | answered | Ofir Gorodetsky | CC BY-SA 3.0 |