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Oct 11, 2016 at 7:24 comment added user26857 @PierreMATSUMI It's really sad that after more than 3 years you did not accept any answer to your questions.
Sep 21, 2016 at 9:38 comment added Wilberd van der Kallen If $g$ is prime, then the answer is yes. One shows that multiplication by $g$ on $S[X]/(f)$ is injective and thus has a nontrivial determinant. And a matrix times its adjoint is the determinant times the identity matrix.
S Sep 21, 2016 at 9:29 history suggested Luc Guyot CC BY-SA 3.0
Slight change which makes the question easier to grasp (at least for me)
Sep 21, 2016 at 9:19 review Suggested edits
S Sep 21, 2016 at 9:29
Sep 21, 2016 at 8:08 answer added Wilberd van der Kallen timeline score: 6
S Sep 21, 2016 at 7:59 history suggested SashaP CC BY-SA 3.0
Enabled MathJax and removed unnecessary tags
Sep 21, 2016 at 7:58 review Close votes
Sep 24, 2016 at 2:51
Sep 21, 2016 at 7:52 comment added SashaP Why not if, for example $\deg f=0$?
Sep 21, 2016 at 7:51 review Suggested edits
S Sep 21, 2016 at 7:59
Sep 21, 2016 at 6:06 history asked Pierre MATSUMI CC BY-SA 3.0