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Sep 17, 2016 at 15:13 answer added YCor timeline score: 8
Sep 17, 2016 at 12:18 comment added Geoff Robinson Clearly if $G$ itself is not elementary, then $G$ has strictly fewer maximal subgroups than an elementary Abelian group of order $|G|$ does, so that's a start.
Sep 17, 2016 at 12:14 history edited aya
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Sep 17, 2016 at 12:13 review Close votes
Sep 17, 2016 at 16:41
Sep 17, 2016 at 11:51 history asked aya CC BY-SA 3.0