Timeline for Product of complex numbers in same complex partition as factors
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 14, 2016 at 4:24 | answer | added | Aaron Meyerowitz | timeline score: 0 | |
| Sep 14, 2016 at 3:08 | history | edited | Dave Lampert | CC BY-SA 3.0 |
Improved definition of B and rephrased entire question for clarity
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| Sep 13, 2016 at 21:57 | comment | added | Igor Rivin | @DaveLampert Duh, you are right, but see my answer. | |
| Sep 13, 2016 at 21:26 | comment | added | Dave Lampert | @Igor Rivin - if B(0) = 17, then B(0*0) = B(0) * B(0) means that 17 = 17 * 17, which of course isn't correct. That's why B would most likely have values of 0 or 1, but I can't prove that. | |
| Sep 13, 2016 at 21:24 | comment | added | Dave Lampert | @Qiaochu Yuan - Yes, B is a function that takes a complex number "x" as input, and returns a number, presumably a 0 or 1, to identify which half of the bisected complex space "x" falls in. | |
| Sep 13, 2016 at 20:39 | answer | added | Igor Rivin | timeline score: 1 | |
| Sep 13, 2016 at 20:27 | comment | added | Qiaochu Yuan | I don't understand your question. What is $B$? Is it a function that takes as input complex numbers? If so, what does it return as output? | |
| Sep 13, 2016 at 20:23 | comment | added | Igor Rivin | Yes. $B(0) = 17,$ $B(x) = 1,$ whenever $x\neq 0.$ | |
| Sep 13, 2016 at 20:15 | review | First posts | |||
| Sep 13, 2016 at 20:18 | |||||
| Sep 13, 2016 at 20:14 | history | asked | Dave Lampert | CC BY-SA 3.0 |