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Timeline for Coinciding induced maps

Current License: CC BY-SA 2.5

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May 17, 2010 at 21:36 vote accept AAK
May 17, 2010 at 15:50 comment added Torsten Ekedahl It is enough that the source complex is projective (or the target complex injective) to construct things inductively. If you like you can replace $B$ in my example by $\mathbb Q/\mathbb Z$ in degrees $0$ and $1$ with a suitable map $A \to B$ and get the same counterexample.
May 17, 2010 at 10:41 comment added Qfwfq @adeel: Isn't $\mathbb{Z}$ a projective module? And aren't the above complexes (in Ekedahl's answer) bounded?
May 17, 2010 at 8:11 history edited Torsten Ekedahl CC BY-SA 2.5
Corrected mixup between left and right.
May 17, 2010 at 7:57 history answered Torsten Ekedahl CC BY-SA 2.5