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Mar 20, 2021 at 19:29 history edited Skip CC BY-SA 4.0
Previous version said the D6 was SO, but in fact it is a half-spin group. This correction does not alter the rest of the answer
Oct 12, 2016 at 21:33 vote accept nxir
Oct 12, 2016 at 21:33 comment added nxir Hello Skip. After grinding through all the stuff you mentioned, i really have to thank you. In case you read my question again, you will notice that i was under the assumption that a there has to be some quadratic form p, whose splitting pattern is reflected in the possible "patterns" of Tits-Indexes. Your second last sentence does additionally clean my confusion. Passing to k(SB(A)) splits A (of course), but doesnt effect the anisotropic kernel of G.
Sep 12, 2016 at 23:11 history answered Skip CC BY-SA 3.0