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May 6, 2017 at 20:47 review Close votes
May 7, 2017 at 0:10
May 6, 2017 at 20:24 comment added YCor It sounds trivial. If we have an inductive limit of $(G_n)$ with arrows $f_n:G_n\to G_{n+1}$, then it's canonically isomorphic to the inductive limit of $(G_{2n+1})$ with the maps $f_{2n+2}\circ f_{2n+1}$. It works in any category.
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Sep 8, 2016 at 12:34 answer added Igor Khavkine timeline score: 0
Sep 8, 2016 at 11:55 history edited André Henriques CC BY-SA 3.0
Fixed the latex
Sep 8, 2016 at 11:50 review First posts
Sep 8, 2016 at 12:38
Sep 8, 2016 at 11:45 history asked user101496 CC BY-SA 3.0