Timeline for show that $ \frac{\Gamma(\frac{1}{24})\Gamma(\frac{11}{24})}{\Gamma(\frac{5}{24})\Gamma(\frac{7}{24})} = \sqrt{3}\cdot \sqrt{2 + \sqrt{3}} $
Current License: CC BY-SA 3.0
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| Sep 12, 2016 at 17:05 | comment | added | Igor Rivin | @NoamD.Elkies Yes, but the duplication formula at the end of the section gets you to $1/24,$ I think. | |
| Sep 12, 2016 at 1:00 | comment | added | Noam D. Elkies | That discussion concerns relations among the values of $\Gamma$ at multiples of $1/12$, not $1/24$ (though the technique can indeed be adapted to the present question). | |
| Sep 6, 2016 at 15:25 | history | answered | Igor Rivin | CC BY-SA 3.0 |